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16x^2+9x^2=625
We move all terms to the left:
16x^2+9x^2-(625)=0
We add all the numbers together, and all the variables
25x^2-625=0
a = 25; b = 0; c = -625;
Δ = b2-4ac
Δ = 02-4·25·(-625)
Δ = 62500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{62500}=250$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-250}{2*25}=\frac{-250}{50} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+250}{2*25}=\frac{250}{50} =5 $
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